$A$ transistor having $\alpha = 0.99$ is used in a common base amplifier. If the load resistance is $4.5 \, k\Omega$ and the dynamic resistance of the emitter junction is $50 \, \Omega$,the voltage gain of the amplifier will be:

$A$ transistor having a $\beta$ equal to $80$ has a change in base current of $250 \mu A$. What is the change in collector current?

The voltage gain of a transistor in common emitter configuration is $160$. The resistances in base and collector sides of the circuit are $1 \text{ k}\Omega$ and $4 \text{ k}\Omega$ respectively. If the change in base current is $100 \mu A$, then the change in output current is:

In common emitter mode of a transistor, the d.c. current gain is $20$, and the emitter current is $7 \,mA$. The collector current is (in $/ 3 \,mA$)

The value of $I_c$ for the configuration shown is in $mA$.

In the circuit shown, the value of $\beta$ of the transistor is $48$. If the base current supplied is $200 \mu A$, what is the voltage at the terminal $Y$ (in $V$)?