The voltage gain of a transistor in common em | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a transistor in common emitter configuration, the voltage gain $A_V$ is given by the product of current gain $\beta$ and resistance gain $R_C/

Vedclass · Accepted Answer

$4 	ext{ mA}$

Vedclass · Answer

(A) For a transistor in common emitter configuration, the voltage gain $A_V$ is given by the product of current gain $\beta$ and resistance gain $R_C/R_B$.$A_V = \beta 	imes \frac{R_C}{R_B}$Given: $A_V = 160$, $R_B = 1 	ext{ k}\Omega$, $R_C = 4 	ext{ k}\Omega$, and $\Delta I_B = 100 \mu A$.We know that $\beta = \frac{\Delta I_C}{\Delta I_B}$.Substituting this into the voltage gain formula:$A_V = \left(\frac{\Delta I_C}{\Delta I_B}ight) 	imes \frac{R_C}{R_B}$$160 = \left(\frac{\Delta I_C}{100 	imes 10^{-6} 	ext{ A}}ight) 	imes \left(\frac{4 	ext{ k}\Omega}{1 	ext{ k}\Omega}ight)$$160 = \left(\frac{\Delta I_C}{100 	imes 10^{-6}}ight) 	imes 4$$40 = \frac{\Delta I_C}{100 	imes 10^{-6}}$$\Delta I_C = 40 	imes 100 	imes 10^{-6} 	ext{ A} = 4000 	imes 10^{-6} 	ext{ A} = 4 	imes 10^{-3} 	ext{ A} = 4 	ext{ mA}$.Thus, the change in output current is $4 	ext{ mA}$.

The voltage gain of a transistor in common emitter configuration is $160$. The resistances in base and collector sides of the circuit are $1 \text{ k}\Omega$ and $4 \text{ k}\Omega$ respectively. If the change in base current is $100 \mu A$, then the change in output current is:

Similar Questions

In a common base mode of a transistor,the collector current is $5.488 \ mA$ for an emitter current of $5.60 \ mA$. The value of the base current amplification factor $(\beta)$ will be

For a transistor,$\alpha_{dc}$ and $\beta_{dc}$ are the current ratios. Then the value of $\frac{\beta_{dc}-\alpha_{dc}}{\alpha_{dc} \cdot \beta_{dc}}$ is

The ratio $(R)$ of output resistance $r_0$ and input resistance $r_i$ in measurements of input and output characteristics of a transistor is typically in the range:

In an $n-p-n$ transistor circuit,the collector current is $10 \, mA$. If $90 \%$ of the electrons reach the collector,then the emitter current will be:

The current amplification factor of a transistor is $50$. The input resistance when used in common emitter mode is $1 \text{ k}\Omega$. The peak value of the collector current for an a.c. input voltage of $0.01 \text{ V}$ peak is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module