For a gas, frac{R}{C_v} = 0.4, where R is the | vedclass

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(D) We are given the relation $\frac{R}{C_v} = 0.4$, which implies $C_v = \frac{R}{0.4} = 2.5R$.For an ideal gas, the molar specific heat at constant

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rigid diatomic

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(D) We are given the relation $\frac{R}{C_v} = 0.4$, which implies $C_v = \frac{R}{0.4} = 2.5R$.For an ideal gas, the molar specific heat at constant volume is given by $C_v = \frac{f}{2}R$, where $f$ is the number of degrees of freedom.Equating the two expressions: $\frac{f}{2}R = 2.5R$.This gives $f = 5$.$A$ gas molecule with $f = 5$ degrees of freedom corresponds to a rigid diatomic molecule ($3$ translational + $2$ rotational degrees of freedom).Therefore, the gas is rigid diatomic.

For a gas, $\frac{R}{C_v} = 0.4$, where $R$ is the universal gas constant and $C_v$ is the molar specific heat at constant volume. The gas is made up of molecules which are

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