For a gas,frac{R}{C_{V}}=0.4,where R is the u | vedclass

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(A) Given: $\frac{R}{C_{V}} = 0.4$$C_{V} = \frac{R}{0.4} = \frac{R}{2/5} = \frac{5R}{2}$We know that for an ideal gas,$C_{P} = C_{V} + R$.Substituting

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rigid diatomic

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(A) Given: $\frac{R}{C_{V}} = 0.4$$C_{V} = \frac{R}{0.4} = \frac{R}{2/5} = \frac{5R}{2}$We know that for an ideal gas,$C_{P} = C_{V} + R$.Substituting the value of $C_{V}$:$C_{P} = \frac{5R}{2} + R = \frac{7R}{2}$The adiabatic index $\gamma$ is given by $\gamma = \frac{C_{P}}{C_{V}}$.$\gamma = \frac{7R/2}{5R/2} = \frac{7}{5} = 1.4$For a gas,the degree of freedom $f$ is related to $\gamma$ by $\gamma = 1 + \frac{2}{f}$.$1.4 = 1 + \frac{2}{f} \implies 0.4 = \frac{2}{f} \implies f = \frac{2}{0.4} = 5$.$A$ gas with $f = 5$ degrees of freedom corresponds to rigid diatomic molecules.

For a gas,$\frac{R}{C_{V}}=0.4$,where $R$ is the universal gas constant and $C_{V}$ is the molar specific heat at constant volume. The gas is made up of molecules which are

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