For a given frequency distribution,A = 200,Si | vedclass

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(B) The formula for the mean using the step-deviation method is $\bar{x} = A + \left( \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} ight) 	imes c$.Given

Vedclass · Accepted Answer

$152$

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(B) The formula for the mean using the step-deviation method is $\bar{x} = A + \left( \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} ight) 	imes c$.Given values are $A = 200$,$\Sigma f_{i} = 45$,$\Sigma f_{i} u_{i} = -216$,and $c = 10$.Substituting these values into the formula:$\bar{x} = 200 + \left( \frac{-216}{45} ight) 	imes 10$$\bar{x} = 200 + \left( \frac{-2160}{45} ight)$$\bar{x} = 200 - 48$$\bar{x} = 152$.

Class	$0-100$	$100-200$	$200-300$	$300-400$	$400-500$	$500-600$	$600-700$	$700-800$	$800-900$	$900-1000$
Frequency	$2$	$5$	$x$	$12$	$17$	$20$	$y$	$9$	$7$	$4$

For a given frequency distribution,$A = 200$,$\Sigma f_{i} = 45$,$\Sigma f_{i} u_{i} = -216$ and $c = 10$. Then,mean $\bar{x} = \dots$

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