In the formula Z = l + left( frac{f_{1} - f_{ | vedclass

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(D) In the formula for calculating the mode of grouped data,the variables are defined as follows:$Z$ is the mode.$l$ is the lower limit of the modal c

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frequency of the class succeeding the modal class

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(D) In the formula for calculating the mode of grouped data,the variables are defined as follows:$Z$ is the mode.$l$ is the lower limit of the modal class.$f_{1}$ is the frequency of the modal class.$f_{0}$ is the frequency of the class preceding the modal class.$f_{2}$ is the frequency of the class succeeding the modal class.$c$ is the size of the class interval.Therefore,$f_{2}$ represents the frequency of the class succeeding the modal class.

Daily wages (in $Rs.$)	Number of workers
$100-120$	$10$
$120-140$	$15$
$140-160$	$20$
$160-180$	$22$
$180-200$	$18$
$200-220$	$12$
$220-240$	$13$

In the formula $Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$ for the mode,$f_{2} = \ldots \ldots \ldots$

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Daily wages of $110$ workers,obtained in a survey,are tabulated below:

Daily wages (in $Rs.$) Number of workers

$100-120$ $10$

$120-140$ $15$

$140-160$ $20$

$160-180$ $22$

$180-200$ $18$

$200-220$ $12$

$220-240$ $13$

Compute the mean daily wages of these workers (in $Rs.$).

Calculate the mean of the following frequency distribution:

Class $80-90$ $90-100$ $100-110$ $110-120$ $120-130$ $130-140$ $140-150$ $150-160$ $160-170$

Frequency $6$ $18$ $78$ $80$ $100$ $72$ $0$ $40$ $6$
(in $.55$)

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