Calculate the mean of the following frequency | vedclass

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(D) To calculate the mean,we use the formula $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$,where $x_i$ is the class mark.$1$. Calculate class marks $(x_i)

Vedclass · Accepted Answer

$122$

Vedclass · Answer

(D) To calculate the mean,we use the formula $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$,where $x_i$ is the class mark.$1$. Calculate class marks $(x_i)$: $85, 95, 105, 115, 125, 135, 145, 155, 165$.$2$. Calculate $f_i x_i$:$6 	imes 85 = 510$$18 	imes 95 = 1710$$78 	imes 105 = 8190$$80 	imes 115 = 9200$$100 	imes 125 = 12500$$72 	imes 135 = 9720$$0 	imes 145 = 0$$40 	imes 155 = 6200$$6 	imes 165 = 990$$3$. Sum of frequencies $\sum f_i = 6 + 18 + 78 + 80 + 100 + 72 + 0 + 40 + 6 = 400$.$4$. Sum of products $\sum f_i x_i = 510 + 1710 + 8190 + 9200 + 12500 + 9720 + 0 + 6200 + 990 = 49020$.$5$. Mean $\bar{x} = \frac{49020}{400} = 122.55$.

Class	$20-25$	$25-30$	$30-35$	$35-40$	$40-45$	$45-50$	$50-55$
Frequency	$2$	$5$	$8$	$10$	$7$	$10$	$3$

Weight (in $g$)	Number of packets
$200-201$	$12$
$201-202$	$26$
$202-203$	$20$
$203-204$	$9$
$204-205$	$2$
$205-206$	$1$

Calculate the mean of the following frequency distribution:

Class $80-90$ $90-100$ $100-110$ $110-120$ $120-130$ $130-140$ $140-150$ $150-160$ $160-170$

Frequency $6$ $18$ $78$ $80$ $100$ $72$ $0$ $40$ $6$
(in $.55$)

Similar Questions

The median class in the following frequency distribution is ..........

Class $20-25$ $25-30$ $30-35$ $35-40$ $40-45$ $45-50$ $50-55$

Frequency $2$ $5$ $8$ $10$ $7$ $10$ $3$

For some given data, if $M = 15.4$ and $\bar{x} = 14.5$, then $Z = \dots$

The formula to find the mode of a grouped data is $\ldots \ldots \ldots . . .$

The weight of coffee in $70$ packets is shown in the following table:

Weight (in $g$) Number of packets

$200-201$ $12$

$201-202$ $26$

$202-203$ $20$

$203-204$ $9$

$204-205$ $2$

$205-206$ $1$

Determine the modal weight (in $g$).

In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$h = \ldots \ldots \ldots$

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Calculate the mean of the following frequency distribution: Class $80-90$ $90-100$ $100-110$ $110-120$ $120-130$ $130-140$ $140-150$ $150-160$ $160-170$ Frequency $6$ $18$ $78$ $80$ $100$ $72$ $0$ $40$ $6$ (in $.55$)