In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$h = \ldots \ldots \ldots$
- Acumulative frequency of the class preceding the median class
- Bfrequency of the median class
- Cclass size (class length)
- Dlower limit of the median class
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Similar Questions
If $Z=12$ and $M=16,$ then $\bar{x}=$ ............
Medium
View SolutionIf $M - \bar{x} = 2$ and $Z = 20.5$,then the median $M = \ldots$ (in $.5$)
Medium
View SolutionIn the formula $Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$ for the mode,$f_{1} = \ldots \ldots \ldots$
Easy
View SolutionThe daily income of a sample of $50$ employees is tabulated as follows:
Income (in $Rs.$) $1-200$ $201-400$ $401-600$ $601-800$ Number of employees $14$ $15$ $14$ $7$
Find the mean daily income of the employees. (in $.5$)
| Income (in $Rs.$) | $1-200$ | $201-400$ | $401-600$ | $601-800$ |
| Number of employees | $14$ | $15$ | $14$ | $7$ |
Find the mean daily income of the employees. (in $.5$)
Difficult
View SolutionThe median class in the following frequency distribution is ..........
Class $20-25$ $25-30$ $30-35$ $35-40$ $40-45$ $45-50$ $50-55$ Frequency $2$ $5$ $8$ $10$ $7$ $10$ $3$
| Class | $20-25$ | $25-30$ | $30-35$ | $35-40$ | $40-45$ | $45-50$ | $50-55$ |
| Frequency | $2$ | $5$ | $8$ | $10$ | $7$ | $10$ | $3$ |
Easy
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