(C) In the formula for the mode of grouped data,$Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$,the term $f_{1}$ repres

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(C) In the formula for the mode of grouped data,$Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$,the term $f_{1}$ represents the frequency of the modal class. Here,$l$ is the lower limit of the modal class,$f_{0}$ is the frequency of the class preceding the modal class,$f_{2}$ is the frequency of the class succeeding the modal class,and $c$ is the class size (or class length).

Class 10 Mathematics Statistics Mix Examples - Statistics

Easy

In the formula $Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$ for the mode,$f_{1} = \ldots \ldots \ldots$

A
frequency of the class preceding the modal class
B
class length
C
frequency of the modal class
D
frequency of the class succeeding the modal class

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Mix Examples - Statistics

Consider the following frequency distribution of the heights of $60$ students of a class:

Height (in $cm$) Number of students

$150-155$ $15$

$155-160$ $13$

$160-165$ $10$

$165-170$ $8$

$170-175$ $9$

$175-180$ $5$

The sum of the lower limit of the modal class and upper limit of the median class is:

Easy

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Find the mean of the distribution:

Class $1-3$ $3-5$ $5-7$ $7-10$

Frequency $9$ $22$ $27$ $17$

Medium

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Find the mean of the following data by all the three methods:

Class $50-70$ $70-90$ $90-110$ $110-130$ $130-150$ $150-170$

Frequency $10$ $18$ $7$ $6$ $5$ $4$

Medium

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The mean of the following data is $55.5$ and the total frequency is $20$. Find the missing frequencies $x$ and $y$.
Class $30-40$ $40-50$ $50-60$ $60-70$ $70-80$
Frequency $3$ $x$ $7$ $7$ $y$

Medium

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For a given frequency distribution,the frequencies of the first,second,and third class are $8$,$15$,and $18$ respectively. Then,the cumulative frequency of the third class is $\ldots \ldots \ldots \ldots .$

Easy

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Height (in $cm$)	Number of students
$150-155$	$15$
$155-160$	$13$
$160-165$	$10$
$165-170$	$8$
$170-175$	$9$
$175-180$	$5$

Class	$50-70$	$70-90$	$90-110$	$110-130$	$130-150$	$150-170$
Frequency	$10$	$18$	$7$	$6$	$5$	$4$

Class	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
Frequency	$3$	$x$	$7$	$7$	$y$

In the formula $Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$ for the mode,$f_{1} = \ldots \ldots \ldots$

Similar Questions

Consider the following frequency distribution of the heights of $60$ students of a class: Height (in $cm$) Number of students $150-155$ $15$ $155-160$ $13$ $160-165$ $10$ $165-170$ $8$ $170-175$ $9$ $175-180$ $5$ The sum of the lower limit of the modal class and upper limit of the median class is:

Find the mean of the distribution: Class $1-3$ $3-5$ $5-7$ $7-10$ Frequency $9$ $22$ $27$ $17$

Find the mean of the following data by all the three methods: Class $50-70$ $70-90$ $90-110$ $110-130$ $130-150$ $150-170$ Frequency $10$ $18$ $7$ $6$ $5$ $4$

The mean of the following data is $55.5$ and the total frequency is $20$. Find the missing frequencies $x$ and $y$.Class$30-40$$40-50$$50-60$$60-70$$70-80$Frequency$3$$x$$7$$7$$y$

For a given frequency distribution,the frequencies of the first,second,and third class are $8$,$15$,and $18$ respectively. Then,the cumulative frequency of the third class is $\ldots \ldots \ldots \ldots .$

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Find the mean of the distribution:

Class $1-3$ $3-5$ $5-7$ $7-10$

Frequency $9$ $22$ $27$ $17$

Find the mean of the following data by all the three methods:

Class $50-70$ $70-90$ $90-110$ $110-130$ $130-150$ $150-170$

Frequency $10$ $18$ $7$ $6$ $5$ $4$

The mean of the following data is $55.5$ and the total frequency is $20$. Find the missing frequencies $x$ and $y$.
Class $30-40$ $40-50$ $50-60$ $60-70$ $70-80$
Frequency $3$ $x$ $7$ $7$ $y$