For a given frequency distribution,bar{x}=20, | vedclass

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(A) The formula for the mean using the step-deviation method is given by: $\bar{x} = A + \left( \frac{\Sigma f_{i} u_{i}}{n} ight) 	imes c$Given va

Vedclass · Accepted Answer

$25$

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(A) The formula for the mean using the step-deviation method is given by: $\bar{x} = A + \left( \frac{\Sigma f_{i} u_{i}}{n} ight) 	imes c$Given values are: $\bar{x} = 20$,$\Sigma f_{i} u_{i} = -50$,$n = 100$,and $c = 10$.Substituting these values into the formula:$20 = A + \left( \frac{-50}{100} ight) 	imes 10$Simplify the expression:$20 = A + (-0.5) 	imes 10$$20 = A - 5$Solving for $A$:$A = 20 + 5$$A = 25$Thus,the assumed mean $A$ is $25$.

Class	$60-70$	$70-80$	$80-90$	$90-100$	$100-110$	$110-120$
Frequency	$5$	$15$	$20$	$30$	$20$	$8$

Class	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$	$80-90$	$90-100$
Frequency	$5$	$7$	$12$	$10$	$8$	$6$	$2$

For a given frequency distribution,$\bar{x}=20, \Sigma f_{i} u_{i}=-50, n=100$ and $c=10$. Then,assumed mean $A = \ldots \ldots \ldots \ldots$

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$\Sigma(x_{i} - \bar{x}) = \ldots \ldots \ldots$

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