For a given reaction $t_{1/2} = \frac{1}{Ka}$. The order of the reaction is

  • A
    $1$
  • B
    $0$
  • C
    $3$
  • D
    $2$

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Acid catalysed hydrolysis of ethyl acetate follows a pseudo-first order kinetics with respect to ester. If the reaction is carried out with large excess of ester, the order with respect to ester will be

For the reaction between $A$ and $B$,the initial rate of reaction $(r_0)$ was measured for different initial concentrations of $A$ and $B$ as given below. Determine the order of the reaction with respect to $A$ and $B$ respectively.
$[A] / mol \ L^{-1}$$0.2, 0.2, 0.4$
$[B] / mol \ L^{-1}$$0.3, 0.1, 0.05$
$r_0 / mol \ L^{-1} s^{-1}$$5.0 \times 10^{-5}, 5.0 \times 10^{-5}, 1.4 \times 10^{-4}$

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For a reaction,$A + B \longrightarrow$ Product; the rate law is given by $r = k[A]^2[B]^{1/2}$. What is the order of the reaction?

Which of the following determines the rate of a multistep reaction?

The following results are obtained for the reaction $S + Nu \rightarrow \text{product}$. By which reaction mechanism does this reaction occur?
Experiment $[S]$ $[Nu]$ Rate
$1$ $0.1$ $0.1$ $2.2 \times 10^{-3}$
$2$ $0.2$ $0.1$ $4.4 \times 10^{-3}$
$3$ $0.1$ $0.2$ $4.4 \times 10^{-3}$

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