For a given surface,the Gauss's law is stated as $\oint {E \cdot ds} = 0$. From this,we can conclude that:
- A$E$ is necessarily zero on the surface
- B$E$ is perpendicular to the surface at every point
- CThe total flux through the surface is zero
- DThe flux is only going out of the surface
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$A$ square surface of side $L$ meters is in the plane of the paper. $A$ uniform electric field $\vec{E} \text{ (V/m)}$ is also in the plane of the paper,limited only to the lower half of the square surface. The electric flux associated with the surface in $SI$ units is:
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