For a metal ion,the calculated magnetic momen | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnetic moment $\mu$ is related to the number of unpaired electrons $n$ by the formula: $\mu = \sqrt{n(n+2)} \ BM$. Given $\mu = 4.90 \ BM$,w

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(C) The magnetic moment $\mu$ is related to the number of unpaired electrons $n$ by the formula: $\mu = \sqrt{n(n+2)} \ BM$. Given $\mu = 4.90 \ BM$,we have $4.90 = \sqrt{n(n+2)}$. Squaring both sides,we get $24.01 = n(n+2)$,which is approximately $n^2 + 2n - 24 = 0$. Solving this quadratic equation,$(n+6)(n-4) = 0$. Since $n$ must be positive,$n = 4$. Thus,the metal ion has $4$ unpaired electrons.

For a metal ion,the calculated magnetic moment is $4.90 \ BM$. This metal ion has $........$ number of unpaired electrons.

Similar Questions

The highest value of the calculated spin-only magnetic moment (in $BM$) among all the transition metal complexes is

The magnetic moment (spin-only) of $[NiCl_4]^{2-}$ is ........ $B.M.$

The pair in which both the species have the same magnetic moment (spin only) is

The number of isomers possible for the octahedral complex $[CoCl_{2}(en)(NH_{3})_{2}]^{+}$ is,

Which one of the following complexes shows optical isomerism? $(en = \text{ethylenediamine})$

Vedclass Test Series

Exam Paper Generator

Online Exam Module