For a metallic wire,the ratio V/i (V = the ap | vedclass

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(B) According to Ohm's law,the ratio $V/i$ is equal to the resistance $R$ of the conductor.For a metallic wire,the resistance $R$ is given by the rela

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Increases as the temperature rises

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(B) According to Ohm's law,the ratio $V/i$ is equal to the resistance $R$ of the conductor.For a metallic wire,the resistance $R$ is given by the relation $R_t = R_0(1 + \alpha \Delta T)$,where $\alpha$ is the temperature coefficient of resistance.For metals,$\alpha$ is positive,which means that as the temperature increases,the resistance $R$ of the metallic wire increases.Therefore,the ratio $V/i$ increases as the temperature rises.

For a metallic wire,the ratio $V/i$ ($V =$ the applied potential difference,$i =$ current flowing) is

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