For a molecular formula of C_6H_{10} of an al | vedclass

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(C) The molecular formula $C_6H_{10}$ corresponds to an alkyne with $6$ carbon atoms. The branched isomers are those that do not have a straight chain

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$4$

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(C) The molecular formula $C_6H_{10}$ corresponds to an alkyne with $6$ carbon atoms. The branched isomers are those that do not have a straight chain of $6$ carbons. The possible branched isomers are: $1$. $3-	ext{methyl}-1-	ext{pentyne}$ $(CH_3-CH_2-CH(CH_3)-C \equiv CH)$ $2$. $4-	ext{methyl}-1-	ext{pentyne}$ $(CH_3-CH(CH_3)-CH_2-C \equiv CH)$ $3$. $3-	ext{methyl}-2-	ext{pentyne}$ $(CH_3-CH_2-C(CH_3)-C \equiv C-CH_3)$ $4$. $3,3-	ext{dimethyl}-1-	ext{butyne}$ $((CH_3)_2C(C \equiv CH)-CH_3)$ Thus,there are $4$ possible branched isomers.

For a molecular formula of $C_6H_{10}$ of an alkyne series,the number of possible branched isomers is

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