(D) Given that the horizontal range $(R)$ is equal to the maximum height $(H)$.$R = \frac{u^2 \sin(2\theta)}{g} = \frac{2u^2 \sin\theta \cos\theta}{g}

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(D) Given that the horizontal range $(R)$ is equal to the maximum height $(H)$.$R = \frac{u^2 \sin(2\theta)}{g} = \frac{2u^2 \sin\theta \cos\theta}{g}$$H = \frac{u^2 \sin^2\theta}{2g}$Equating $R$ and $H$:$\frac{2u^2 \sin\theta \cos\theta}{g} = \frac{u^2 \sin^2\theta}{2g}$Dividing both sides by $\frac{u^2 \sin\theta}{g}$ (assuming $\sin\theta \neq 0$):$2 \cos\theta = \frac{\sin\theta}{2}$$\frac{\sin\theta}{\cos\theta} = 4$$\tan\theta = 4$$\theta = \tan^{-1}(4)$

Class 11 Physics 3-2.Motion in Plane Horizontal Projectile Motion

Medium

For a projectile,the maximum height and horizontal range are same. The angle of projection $\theta$ of the projectile is

MHT CET 2024 All MHT CET

A
$\tan^{-1}\left(\frac{1}{2}\right)$
B
$\tan^{-1}(2)$
C
$\tan^{-1}\left(\frac{1}{4}\right)$
D
$\tan^{-1}(4)$

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3-2.Motion in Plane

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Horizontal Projectile Motion

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If $R$ and $H$ are the horizontal range and maximum height attained by a projectile,then its speed of projection is ..........

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For a projectile,the maximum height and horizontal range are same. The angle of projection $\theta$ of the projectile is

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Two bodies are projected at angles $\theta$ and $(90^\circ - \theta)$ with the same initial velocity. Find the ratio of their times of flight.

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