For a ray of light,the critical angle is mini | vedclass

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(A) The critical angle $c$ for total internal reflection $(TIR)$ when light travels from a medium of refractive index $n_1$ to a medium of lower refra

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glass to air

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(A) The critical angle $c$ for total internal reflection $(TIR)$ when light travels from a medium of refractive index $n_1$ to a medium of lower refractive index $n_2$ is given by $\sin c = \frac{n_2}{n_1}$,where $n_1 > n_2$. The smaller the ratio $\frac{n_2}{n_1}$,the smaller $\sin c$,and hence the smaller the critical angle $c$. From the options,the valid scenarios for $TIR$ are only those in which the first medium has a higher index than the second. For glass to air $(n_{	ext{glass}} \approx 1.5, n_{	ext{air}} \approx 1.0)$: $\sin c = \frac{1.0}{1.5} = \frac{2}{3} \approx 0.667$,which gives $c \approx 41.8^{\circ}$. For glass to water $(n_{	ext{glass}} \approx 1.5, n_{	ext{water}} \approx 1.33)$: $\sin c = \frac{1.33}{1.5} \approx 0.887$,which gives $c \approx 62.5^{\circ}$. Clearly,the critical angle is smaller for glass-to-air. Hence,the critical angle is minimum when light travels from glass to air.

For a ray of light,the critical angle is minimum,when it travels from

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