Medium
For a reaction,$A + B \rightarrow \text{Product}$; the rate law is given by,$r = k[A]^{1/2}[B]^2$. What is the order of the reaction?
- A$1.5$
- B$2.5$
- C$3.0$
- D$0.5$
Explore More
Similar Questions
What will be the unit of the rate constant for the following reaction?
$C_2H_{4(g)} + H_{2(g)} \rightarrow C_2H_{6(g)}$
$C_2H_{4(g)} + H_{2(g)} \rightarrow C_2H_{6(g)}$
Why can’t molecularity of any reaction be equal to zero?
Easy
View SolutionIf $a$ is the initial concentration of the reactant,the half-life period of the reaction of $n^{th}$ order is inversely proportional to
Medium
View SolutionFor a chemical reaction $A + B \rightarrow \text{Product}$,the order is $1$ with respect to $A$ and $B$.
Rate $(mol \ L^{-1} \ s^{-1})$ $[A]$ $(mol \ L^{-1})$ $[B]$ $(mol \ L^{-1})$ $0.10$ $20$ $0.5$ $0.40$ $x$ $0.5$ $0.80$ $40$ $y$
What is the value of $x$ and $y$?
| Rate $(mol \ L^{-1} \ s^{-1})$ | $[A]$ $(mol \ L^{-1})$ | $[B]$ $(mol \ L^{-1})$ |
|---|---|---|
| $0.10$ | $20$ | $0.5$ |
| $0.40$ | $x$ | $0.5$ |
| $0.80$ | $40$ | $y$ |
What is the value of $x$ and $y$?
Write the unit of the rate constant for the following reactions:
$1.$ Fourth order
$2.$ Third order
$1.$ Fourth order
$2.$ Third order
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo