For a thermocouple,the inversion temperature | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The relationship between the neutral temperature $(T_{n})$,the temperature of the cold junction $(T_{c})$,and the inversion temperature $(T_{i})$

Vedclass · Accepted Answer

$40$

Vedclass · Answer

(A) The relationship between the neutral temperature $(T_{n})$,the temperature of the cold junction $(T_{c})$,and the inversion temperature $(T_{i})$ is given by the formula:$T_{n} = \frac{T_{c} + T_{i}}{2}$Given:$T_{i} = 600^{\circ} C$$T_{n} = 320^{\circ} C$Substituting the values into the formula:$320^{\circ} = \frac{T_{c} + 600^{\circ}}{2}$$640^{\circ} = T_{c} + 600^{\circ}$$T_{c} = 640^{\circ} - 600^{\circ}$$T_{c} = 40^{\circ} C$Therefore,the temperature of the cold junction is $40^{\circ} C$.

For a thermocouple,the inversion temperature is $600^{\circ} C$ and the neutral temperature is $320^{\circ} C$. Find the temperature of the cold junction (in $^{\circ} C$)?

Similar Questions

The figure shows a tetrahedron,each side of which has a resistance $r$. Choose the correct diagram$(s)$,which show a two-dimensional equivalent of the tetrahedron.

In the given circuit, the internal resistance of the battery is $0.50\, \Omega$. What is the charge on the plates of the $5\, \mu F$ capacitor in $\mu C$?

Three identical resistors are connected in series,and the total power consumed is $10 \, W$. If they are connected in parallel,what will be the total power consumed in $W$?

Two electric bulbs marked $25\ W - 220\ V$ and $100\ W - 220\ V$ are connected in series to a $440\ V$ supply. Which of the bulbs will fuse?

For the circuits shown in figures $I$ and $II$,the voltmeter reading would be

Vedclass Test Series

Exam Paper Generator

Online Exam Module