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(D) Let the two-digit number be represented as $10x + y$,where $x$ is the tens digit and $y$ is the units digit.According to the problem,the sum of th

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$22$

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(D) Let the two-digit number be represented as $10x + y$,where $x$ is the tens digit and $y$ is the units digit.According to the problem,the sum of the digits is equal to the product of the digits:$x + y = xy$Rearranging the equation:$xy - x - y = 0$Adding $1$ to both sides to factorize:$xy - x - y + 1 = 1$$(x - 1)(y - 1) = 1$Since $x$ and $y$ are digits ($1$ to $9$ for $x$,$0$ to $9$ for $y$),the only integer solution for $(x - 1)(y - 1) = 1$ is:$x - 1 = 1 \implies x = 2$$y - 1 = 1 \implies y = 2$Thus,the number is $10(2) + 2 = 22$.

For a two-digit number,if the sum of its digits is equal to the product of its digits,then the number is .............

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