For a two-input AND gate,the four entries are | vedclass

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(B) The logic operation for an $AND$ gate is defined by the Boolean expression $Y = A \cdot B$.This means the output $Y$ is $1$ only if both inputs $A

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$1, 2$ and $3$ only

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(B) The logic operation for an $AND$ gate is defined by the Boolean expression $Y = A \cdot B$.This means the output $Y$ is $1$ only if both inputs $A$ and $B$ are $1$. Otherwise,the output $Y$ is $0$.Let us evaluate the given entries:Entry $1$: $A=0, B=1$. $Y = 0 \cdot 1 = 0$. This is correct.Entry $2$: $A=1, B=0$. $Y = 1 \cdot 0 = 0$. This is correct.Entry $3$: $A=1, B=1$. $Y = 1 \cdot 1 = 1$. This is correct.Entry $4$: $A=0, B=0$. $Y = 0 \cdot 0 = 0$. The table shows $Y=1$,which is incorrect.Therefore,entries $1, 2,$ and $3$ are correct.

For a two-input $AND$ gate,the four entries are shown in the truth table. Identify the correct ones out of these ($A, B =$ input,$Y =$ output).
Entry $A$ $B$ $Y$
$1$ $0$ $1$ $0$
$2$ $1$ $0$ $0$
$3$ $1$ $1$ $1$
$4$ $0$ $0$ $1$

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For a two-input $AND$ gate,the four entries are shown in the truth table. Identify the correct ones out of these ($A, B =$ input,$Y =$ output).Entry$A$$B$$Y$$1$$0$$1$$0$$2$$1$$0$$0$$3$$1$$1$$1$$4$$0$$0$$1$