For a wire,$\frac{R}{l} = \frac{1}{2} \, \Omega/cm$ and the length of the wire is $l = 5 \, cm$. If a potential difference of $1 \, V$ is applied across it,the current through the wire will be: $(R = \text{Resistance})$ (in $A$)
- A$0.4$
- B$4$
- C$25$
- D$2.5$
Explore More
Similar Questions
The variation of current $(i)$ and voltage $(V)$ in a conductor is shown in the diagram below. The resistance of the conductor is ........... $\Omega$.
Easy
View Solution$I-V$ characteristic of a copper wire of length $L$ and area of cross-section $A$ is shown in the figure. The slope of the curve becomes
The $V-I$ graph for a conductor at two different temperatures $T_1$ and $T_2$ is shown. The relationship between $T_1$ and $T_2$ is:
Easy
View SolutionThe $I-V$ graphs for two different electrical appliances $P$ and $Q$ are shown in the diagram. If $R_P$ and $R_Q$ are the resistances of the devices,then:
How is the $V-I$ graph of a material following Ohm's law?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo