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(D) For a zero order reaction,the integrated rate equation is given by: $(a - x) = -kt + a$. Comparing this with the equation of a straight line,$y =

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$-ve$ slope and non-zero intercept

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(D) For a zero order reaction,the integrated rate equation is given by: $(a - x) = -kt + a$. Comparing this with the equation of a straight line,$y = mx + c$,where $y = (a - x)$,$x = t$,$m = -k$,and $c = a$. Since the slope $m = -k$ is negative and the intercept $c = a$ is non-zero (initial concentration),the plot of $(a - x)$ $vs$ time is linear with a negative slope and a non-zero intercept.

For a zero order reaction,the plot of concentration $(a - x)$ $vs$ time is linear with

Similar Questions

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