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(D) For a zero-order reaction,the rate law is $[R] = [R]_0 - kt$. At half-life $(t = t_{1/2})$,$[R] = \frac{[R]_0}{2}$. Substituting these values: $\f

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$I-T, II-F$

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(D) For a zero-order reaction,the rate law is $[R] = [R]_0 - kt$. At half-life $(t = t_{1/2})$,$[R] = \frac{[R]_0}{2}$. Substituting these values: $\frac{[R]_0}{2} = [R]_0 - k t_{1/2} \implies k t_{1/2} = \frac{[R]_0}{2} \implies t_{1/2} = \frac{[R]_0}{2k}$. Comparing this with the given expressions: $I. \ k = \frac{[R]_0}{2 t_{1/2}}$ is True (rearranged from $t_{1/2} = \frac{[R]_0}{2k}$). $II. \ t_{1/2} = \frac{[R]_0}{4k}$ is False (the correct expression is $t_{1/2} = \frac{[R]_0}{2k}$). Therefore,the correct answer is $I-T, II-F$.

Mention True $(T)$ and False $(F)$ statements for the following expressions related to a zero-order reaction $R \to P$:
$I. \ k = \frac{[R]_0}{2 t_{1/2}}$
$II. \ t_{1/2} = \frac{[R]_0}{4k}$

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Mention True $(T)$ and False $(F)$ statements for the following expressions related to a zero-order reaction $R \to P$:$I. \ k = \frac{[R]_0}{2 t_{1/2}}$$II. \ t_{1/2} = \frac{[R]_0}{4k}$