For an $A.P.$,the first term is $5$ and the common difference is $3$. Then,the $15^{th}$ term of the $A.P.$ is..........

Find four numbers in $A.P.$ such that their sum is $36$ and the product of means ($2^{nd}$ and $3^{rd}$ term) exceeds the product of extremes ($1^{st}$ and $4^{th}$ term) by $32.$

For the $A.P.$ $0, \frac{1}{2}, 1, \frac{3}{2}, \ldots,$ the common difference is $\ldots \ldots \ldots \ldots$

The eighth term of an $AP$ is half its second term and the eleventh term exceeds one third of its fourth term by $1$. Find the $15^{\text{th}}$ term.

Find the sum of those integers between $1$ and $500$ which are multiples of $2$ as well as of $5$.

The first term of an $AP$ is $-5$ and the last term is $45$. If the sum of the terms of the $AP$ is $120$,then find the number of terms and the common difference.