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(B) In a $p-V$ diagram, the slope of an adiabatic curve at any point is steeper than that of an isothermal curve at that same point.Let the initial st

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$p_{f} > p_{i}$

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(B) In a $p-V$ diagram, the slope of an adiabatic curve at any point is steeper than that of an isothermal curve at that same point.Let the initial state be $A(p_{i}, V_{i})$.During the reversible isothermal expansion to volume $V_{0}$, the gas moves along the isothermal curve to state $B(p_{2}, V_{0})$, where $p_{2} During the subsequent reversible adiabatic compression from volume $V_{0}$ back to $V_{i}$, the gas moves along an adiabatic curve from state $B(p_{2}, V_{0})$ to state $C(p_{f}, V_{i})$.Since the adiabatic curve is steeper than the isothermal curve, the path from $B$ to $C$ lies above the path from $A$ to $B$ in the $p-V$ plane.Therefore, the final pressure $p_{f}$ at volume $V_{i}$ must be greater than the initial pressure $p_{i}$.Thus, $p_{f} > p_{i}$.

Column $I$	Column $II$
$(A)$ Process $A \rightarrow B$	$(p)$ Internal energy decreases.
$(B)$ Process $B \rightarrow C$	$(q)$ Internal energy increases.
$(C)$ Process $C \rightarrow D$	$(r)$ Heat is lost.
$(D)$ Process $D \rightarrow A$	$(s)$ Heat is gained.
	$(t)$ Work is done on the gas.

Similar Questions

Two samples $A$ and $B$ of a gas,initially at the same pressure and temperature,are compressed from volume $V$ to $V/2$. Sample $A$ is compressed isothermally,and sample $B$ is compressed adiabatically. The final pressure of $A$ is:

For an ideal gas,which of the following statements is correct?

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