For each binary operation $^*$ defined below,determine whether $^*$ is commutative or associative. On $Z$,define $a ^* b = a - b$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
On $Z$,$^*$ is defined by $a ^* b = a - b$.
It can be observed that $1 ^* 2 = 1 - 2 = -1$ and $2 ^* 1 = 2 - 1 = 1$.
$\therefore 1 ^* 2 \neq 2 ^* 1$,where $1, 2 \in Z$.
Hence,the operation $^*$ is not commutative.
Also,we have:
$(1 ^* 2) ^* 3 = (1 - 2) ^* 3 = -1 ^* 3 = -1 - 3 = -4$.
$1 ^* (2 ^* 3) = 1 ^* (2 - 3) = 1 ^* (-1) = 1 - (-1) = 2$.
$\therefore (1 ^* 2) ^* 3 \neq 1 ^* (2 ^* 3)$,where $1, 2, 3 \in Z$.
Hence,the operation $^*$ is not associative.

Explore More

Similar Questions

Let $^*$ be a binary operation on the set $Q$ of rational numbers defined as $a ^* b = a - b$. Determine whether the operation $^*$ is commutative and associative.

For any two real numbers,an operation $*$ defined by $a * b = 1 + ab$ is

The set $\{-1, 0, 1\}$ is not a multiplicative group because of the failure of

For each binary operation $^*$ defined below,determine whether $^*$ is commutative or associative. On $Z^+$,define $a ^* b = a^b$.

In the set of integers $(Z, *)$,if $a * b = a + b - n, \forall a, b \in Z$,where $n$ is a fixed integer,then the inverse of $(-n)$ is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo