For the given system,find the tension T_2 in | vedclass

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(D) For block $B$ (mass $m$): Resolving forces horizontally: $T_1 \sin 	heta_1 = mg$ Resolving forces vertically: $T_1 \cos 	heta_1 = mg$ Squaring a

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$\sqrt{5} \, mg$

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(D) For block $B$ (mass $m$): Resolving forces horizontally: $T_1 \sin 	heta_1 = mg$ Resolving forces vertically: $T_1 \cos 	heta_1 = mg$ Squaring and adding: $T_1^2 (\sin^2 	heta_1 + \cos^2 	heta_1) = (mg)^2 + (mg)^2 = 2(mg)^2$ Thus,$T_1 = \sqrt{2} mg$. For block $A$ (mass $m$): Resolving forces horizontally: $T_2 \sin 	heta_2 = T_1 \sin 	heta_1 = mg$ Resolving forces vertically: $T_2 \cos 	heta_2 = mg + T_1 \cos 	heta_1 = mg + \sqrt{2} mg \cos(45^\circ) = mg + \sqrt{2} mg (1/\sqrt{2}) = 2mg$ Squaring and adding: $T_2^2 (\sin^2 	heta_2 + \cos^2 	heta_2) = (mg)^2 + (2mg)^2 = 5(mg)^2$ Therefore,$T_2 = \sqrt{5} mg$.

For the given system,find the tension $T_2$ in the upper string.

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