In the given figure, the blocks A, B, and C w | vedclass

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(B) Let the masses be $m_A = 4 \ kg$, $m_B = 6 \ kg$, and $m_C = 8 \ kg$. The coefficient of friction $\mu = 0.5$ and $g = 10 \ m/s^2$.$1$. Friction b

Vedclass · Accepted Answer

$210$

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(B) Let the masses be $m_A = 4 \ kg$, $m_B = 6 \ kg$, and $m_C = 8 \ kg$. The coefficient of friction $\mu = 0.5$ and $g = 10 \ m/s^2$.$1$. Friction between $A$ and $B$: $f_1 = \mu m_A g = 0.5 	imes 4 	imes 10 = 20 \ N$.$2$. Friction between $B$ and $C$: $f_2 = \mu (m_A + m_B) g = 0.5 	imes (4 + 6) 	imes 10 = 50 \ N$.$3$. Friction between $C$ and ground: $f_3 = \mu (m_A + m_B + m_C) g = 0.5 	imes (4 + 6 + 8) 	imes 10 = 90 \ N$.For block $C$ to move with constant speed, the net force on it must be zero.Let $T$ be the tension in the string. Block $B$ is connected to the wall via a pulley, so for block $B$ to move, $T = f_1 + f_2 = 20 + 50 = 70 \ N$.For block $C$, the forces acting are the applied force $F$ in one direction, and the friction $f_3$, friction $f_2$ (from block $B$), and tension $T$ in the opposite direction.$F = f_3 + f_2 + T = 90 + 50 + 70 = 210 \ N$.

In the given figure, the blocks $A$, $B$, and $C$ weigh $4 \ kg$, $6 \ kg$, and $8 \ kg$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is . . . . . . $N$. (Use $g = 10 \ m/s^2$)

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