For real gases,the relation between P,V and T | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $(i)$ The van der Waals constant $'a'$ represents the magnitude of intermolecular forces of attraction. Larger molecules with more electrons exhib

Vedclass · Accepted Answer

$(i) CO_2, (ii) H_2$

Vedclass · Answer

(A) $(i)$ The van der Waals constant $'a'$ represents the magnitude of intermolecular forces of attraction. Larger molecules with more electrons exhibit stronger van der Waals forces. Comparing the given gases,$CO_2$ has the highest molecular mass and number of electrons,thus it has the highest value of $'a'$.$(ii)$ The van der Waals constant $'b'$ represents the excluded volume,which is proportional to the size of the gas molecules. Among the given gases,$H_2$ is the smallest molecule,therefore it has the lowest value of $'b'$.Thus,the correct answer is $(i) CO_2, (ii) H_2$.

For real gases,the relation between $P$,$V$ and $T$ is given by the van der Waals equation,$(P + \frac{an^2}{V^2})(V - nb) = nRT$. For the following gases $CH_4, CO_2, O_2, H_2$,which gas will have $(i)$ highest value of $'a'$ $(ii)$ lowest value of $'b'$?

Similar Questions

The compressibility factor $(Z)$ of a gas is greater than unity at $1 \, atm$ and $273 \, K$. Therefore:

$A$ plot of the compressibility factor $(z)$ vs $P$ is shown below for $H_2, He, N_2, CO_2$ and $SO_2$. Identify the plot for $CO_2$ gas.

One of the assumptions of the kinetic theory of gases is that there is no force of attraction between the molecules of a gas. State and explain the evidence that shows that this assumption is not applicable for real gases.

What are the values of $V_C$,$P_C$,and $T_C$ in terms of van der Waals constants $a$ and $b$?

Gas deviates from ideal gas nature because molecules

Vedclass Test Series

Exam Paper Generator

Online Exam Module