For the cell reaction,$2Ce^{4+} + Co \to 2Ce^{3+} + Co^{2+}$,$E^\circ_{cell}$ is $1.89 \ V$. If $E^\circ_{Co^{2+}/Co} = -0.28 \ V$,then $E^\circ_{Ce^{4+}/Ce^{3+}}$ is equal to:

  • A
    $-1.64 \ V$
  • B
    $+1.64 \ V$
  • C
    $-2.08 \ V$
  • D
    $+2.17 \ V$

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