For the ellipse 3x^2 + 4y^2 = 12,the length o | vedclass

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(B) Given the equation of the ellipse is $3x^2 + 4y^2 = 12$. Dividing both sides by $12$,we get $\frac{x^2}{4} + \frac{y^2}{3} = 1$. Comparing this wi

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$3$

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(B) Given the equation of the ellipse is $3x^2 + 4y^2 = 12$. Dividing both sides by $12$,we get $\frac{x^2}{4} + \frac{y^2}{3} = 1$. Comparing this with the standard form $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$,we have $a^2 = 4$ and $b^2 = 3$. Thus,$a = 2$ and $b = \sqrt{3}$. The length of the latus rectum is given by the formula $\frac{2b^2}{a}$. Substituting the values,we get $\frac{2 	imes 3}{2} = 3$.

For the ellipse $3x^2 + 4y^2 = 12$,the length of the latus rectum is:

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