For the following carbocations, the correct o | vedclass

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(D) The stability of carbocations is determined by electronic effects:$1$. In $II$ $(^+CH_2-OCH_3)$, the oxygen atom has lone pairs that can donate el

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$I < III < II$

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(D) The stability of carbocations is determined by electronic effects:$1$. In $II$ $(^+CH_2-OCH_3)$, the oxygen atom has lone pairs that can donate electron density through resonance ($+M$ effect), completing the octet of the carbon atom, making it the most stable.$2$. In $III$ $(^+CH_2-CH_3)$, the ethyl group provides stability through hyperconjugation and the inductive effect ($+I$ effect) of the methyl group.$3$. In $I$ $(^+CH_2-COCH_3)$, the carbonyl group $(-C=O)$ is a strong electron-withdrawing group ($-I$ and $-M$ effect), which destabilizes the positive charge, making it the least stable.Therefore, the order of stability is $I < III < II$.

For the following carbocations, the correct order of stability is:
$I: ^+CH_2-COCH_3$
$II: ^+CH_2-OCH_3$
$III: ^+CH_2-CH_3$

Similar Questions

Rank the transition states that occur during the following reaction steps in order of increasing stability (least $\to$ most stable):
$1.$ $CH_3-O^+H_2 \to CH_3^+ + H_2O$
$2.$ $(CH_3)_3C-O^+H_2 \to (CH_3)_3C^+ + H_2O$
$3.$ $(CH_3)_2CH-O^+H_2 \to (CH_3)_2CH^+ + H_2O$

Which of the following is not expected to be an intermediate of the following reaction?

Which of the following carbocations is the most stable?

Stability order of the following carbocations:
$(i) CH_3 - C^{+}(OCH_3) - CH_3$
$(ii) CH_3 - C^{+}(CH_3) - CH_3$
$(iii) CH_3 - NH - C^{+}H_2$
$(iv) CH_3 - C^{+}H_2$

The stability of the following carbanions is in the order of:

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For the following carbocations, the correct order of stability is:$I: ^+CH_2-COCH_3$$II: ^+CH_2-OCH_3$$III: ^+CH_2-CH_3$