For the octahedral complexes of Fe^{3+} in SC | vedclass

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(A) The electronic configuration of $Fe^{3+}$ is $[Ar] 3d^5$.Case-$1$: In the presence of $SCN^{-}$ (a weak field ligand),no pairing occurs in the $d$

Vedclass · Accepted Answer

$4$

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(A) The electronic configuration of $Fe^{3+}$ is $[Ar] 3d^5$.Case-$1$: In the presence of $SCN^{-}$ (a weak field ligand),no pairing occurs in the $d$-orbitals. The number of unpaired electrons $(n)$ is $5$.$\mu = \sqrt{n(n+2)} = \sqrt{5(5+2)} = \sqrt{35} \approx 5.91 \ BM$.Case-$2$: In the presence of $CN^{-}$ (a strong field ligand),pairing occurs in the $d$-orbitals. The number of unpaired electrons $(n)$ is $1$.$\mu = \sqrt{n(n+2)} = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \ BM$.Difference in spin-only magnetic moments $= 5.91 - 1.73 = 4.18 \ BM$.Rounding to the nearest integer,the difference is $4$.

For the octahedral complexes of $Fe^{3+}$ in $SCN^{-}$ (thiocyanato-$S$) and in $CN^{-}$ ligand environments,the difference between the spin-only magnetic moments in Bohr magnetons (when approximated to the nearest integer) is
[Atomic number of $Fe = 26$]

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For the octahedral complexes of $Fe^{3+}$ in $SCN^{-}$ (thiocyanato-$S$) and in $CN^{-}$ ligand environments,the difference between the spin-only magnetic moments in Bohr magnetons (when approximated to the nearest integer) is[Atomic number of $Fe = 26$]