For the parabola y^{2} = 4x,the point P whose | vedclass

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(D) The equation of the parabola is $y^{2} = 4x$. Comparing this with $y^{2} = 4ax$,we get $a = 1$. For any point $P(x, y)$ on the parabola,the focal

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$(16, 8)$ or $(16, -8)$

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(D) The equation of the parabola is $y^{2} = 4x$. Comparing this with $y^{2} = 4ax$,we get $a = 1$. For any point $P(x, y)$ on the parabola,the focal distance is given by $x + a$. Given that the focal distance is $17$,we have $x + 1 = 17$,which implies $x = 16$. Substituting $x = 16$ into the parabola equation: $y^{2} = 4(16) = 64$. Thus,$y = \pm 8$. Therefore,the required points are $(16, 8)$ or $(16, -8)$.

For the parabola $y^{2} = 4x$,the point $P$ whose focal distance is $17$ is

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