The focal distance of the point (4, 4) on the | vedclass

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(B) The equation of a parabola with vertex at $(0, 0)$ and symmetric about the $y$-axis is of the form $x^2 = 4ay$.Since the point $(4, 4)$ lies on th

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$5$

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(B) The equation of a parabola with vertex at $(0, 0)$ and symmetric about the $y$-axis is of the form $x^2 = 4ay$.Since the point $(4, 4)$ lies on the parabola,we have $4^2 = 4a(4)$,which implies $16 = 16a$,so $a = 1$.The equation of the parabola is $x^2 = 4y$.The focus of this parabola is $(0, a) = (0, 1)$.The focal distance of a point $(x_1, y_1)$ on the parabola $x^2 = 4ay$ is given by $|y_1 + a|$.Substituting the values,the focal distance is $|4 + 1| = 5$.

The focal distance of the point $(4, 4)$ on the parabola with vertex at $(0, 0)$ and symmetric about the $y$-axis is:

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