For the reaction $2A + 3B \to 4C$,the rate of reaction may be represented as:

  • A
    $r = - \frac{1}{2} \frac{d[A]}{dt} = - \frac{1}{3} \frac{d[B]}{dt} = \frac{1}{4} \frac{d[C]}{dt}$
  • B
    $r = - 2 \frac{d[A]}{dt} = - 3 \frac{d[B]}{dt} = 4 \frac{d[C]}{dt}$
  • C
    $r = - \frac{1}{2} \frac{d[A]}{dt} = \frac{1}{3} \frac{d[B]}{dt} = \frac{1}{4} \frac{d[C]}{dt}$
  • D
    $r = - \frac{d[A]}{dt} = - \frac{d[B]}{dt} = \frac{d[C]}{dt}$

Explore More

Similar Questions

In a reaction $2A + B \to A_2B$,the reactant $A$ will disappear at

For the reaction $2A + B \to A_2B$,the rate of reaction with respect to $A$ is $3.9 \times 10^{-9} \ mol \ L^{-1} \ s^{-1}$. Calculate the rate of consumption of $B$ and the rate of formation of $A_2B$.

The differential rate law for the reaction $H_2 + I_2 \to 2HI$ is

For the reaction,$N_{2(g)} + 3 H_{2(g)} \longrightarrow 2 NH_{3(g)}$,$NH_{3}$ is formed at a rate of $0.088 \ mol \ dm^{-3} \ s^{-1}$. Calculate the consumption rate of $N_{2(g)}$.

The decomposition of $N_{2}O_{5}$ in $CCl_{4}$ at $318 \ K$ has been studied by monitoring the concentration of $N_{2}O_{5}$ in the solution. Initially the concentration of $N_{2}O_{5}$ is $2.33 \ mol \ L^{-1}$ and after $184 \ minutes$,it is reduced to $2.08 \ mol \ L^{-1}$. The reaction takes place according to the equation:
$2N_{2}O_{5(g)} \rightarrow 4NO_{2(g)} + O_{2(g)}$
Calculate the average rate of this reaction in terms of hours,minutes,and seconds. What is the rate of production of $NO_{2}$ during this period?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo