Medium
For the reaction $2 NO_{(g)} + 2 H_{2(g)} \longrightarrow N_{2(g)} + 2 H_2O_{(g)}$ with the rate law $\text{rate} = k[NO]^2[H_2]$,what is the order of reaction with respect to $H_2$ and the overall order of reaction,respectively?
- A$0, 2$
- B$1, 3$
- C$2, 1$
- D$3, 1$
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For the reaction between $A$ and $B$,the initial rate of reaction $(r_0)$ was measured for different initial concentrations of $A$ and $B$ as given below. Determine the order of the reaction with respect to $A$ and $B$ respectively.
$[A] / mol \ L^{-1}$ $0.2, 0.2, 0.4$ $[B] / mol \ L^{-1}$ $0.3, 0.1, 0.05$ $r_0 / mol \ L^{-1} s^{-1}$ $5.0 \times 10^{-5}, 5.0 \times 10^{-5}, 1.4 \times 10^{-4}$
| $[A] / mol \ L^{-1}$ | $0.2, 0.2, 0.4$ |
| $[B] / mol \ L^{-1}$ | $0.3, 0.1, 0.05$ |
| $r_0 / mol \ L^{-1} s^{-1}$ | $5.0 \times 10^{-5}, 5.0 \times 10^{-5}, 1.4 \times 10^{-4}$ |
Difficult
View SolutionFor a given reaction $t_{1/2} = \frac{1}{k \cdot a}$,the order of reaction will be:
Easy
View SolutionThe rate law for the reaction,$NO_{2(g)} + CO_{(g)} \rightarrow NO_{(g)} + CO_{2(g)}$ is given as $R = k[NO_2]^2$. What is the order of reaction with respect to $CO$?
Rate of reaction for $2X + Y \rightarrow 3W + Z$ is $1.2 \times 10^{-4} \ mol \ dm^{-3} \ sec^{-1}$ when $[X] = [Y] = 0.6 \ mol \ dm^{-3}$. Calculate the value of the rate constant if the reaction is first order in $X$ and zero order in $Y$.
In a reaction between $A$ and $B$,the initial rate of reaction $(r_0)$ was measured for different initial concentrations of $A$ and $B$ as given below:
$A / mol \ L^{-1}$ $0.20$ $0.20$ $0.40$ $B / mol \ L^{-1}$ $0.30$ $0.10$ $0.05$ $r_0 / mol \ L^{-1} \ s^{-1}$ $5.07 \times 10^{-5}$ $5.07 \times 10^{-5}$ $1.43 \times 10^{-4}$
What is the order of the reaction with respect to $A$ and $B$?
| $A / mol \ L^{-1}$ | $0.20$ | $0.20$ | $0.40$ |
| $B / mol \ L^{-1}$ | $0.30$ | $0.10$ | $0.05$ |
| $r_0 / mol \ L^{-1} \ s^{-1}$ | $5.07 \times 10^{-5}$ | $5.07 \times 10^{-5}$ | $1.43 \times 10^{-4}$ |
What is the order of the reaction with respect to $A$ and $B$?
Difficult
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