(C) Let the capacitance of each capacitor be $C$.When connected in series,the equivalent capacitance $C_{1}$ is given by $\frac{1}{C_{1}} = \frac{1}{C

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(C) Let the capacitance of each capacitor be $C$.When connected in series,the equivalent capacitance $C_{1}$ is given by $\frac{1}{C_{1}} = \frac{1}{C} + \frac{1}{C} + \frac{1}{C} + \frac{1}{C} = \frac{4}{C}$,so $C_{1} = \frac{C}{4}$.When connected in parallel,the equivalent capacitance $C_{2}$ is given by $C_{2} = C + C + C + C = 4C$.Now,we calculate the ratio $\frac{C_{2}}{C_{1}}$:$\frac{C_{2}}{C_{1}} = \frac{4C}{C/4} = 4 \times 4 = 16$.

Class 12 Physics Electric Potential and Capacitance Equivalent Capacitance of Capacitor connected in Series and Parallel

Medium

Four capacitors of equal capacity have an equivalent capacitance $C_{1}$ when connected in series and an equivalent capacitance $C_{2}$ when connected in parallel. The ratio $\frac{C_{2}}{C_{1}}$ is:

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A
$4$
B
$12$
C
$16$
D
$8$

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Electric Potential and Capacitance

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Equivalent Capacitance of Capacitor connected in Series and Parallel

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Four capacitors of equal capacity have an equivalent capacitance $C_{1}$ when connected in series and an equivalent capacitance $C_{2}$ when connected in parallel. The ratio $\frac{C_{2}}{C_{1}}$ is:

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