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(C) Let $n = 4$ be the number of trials.The probability of drawing a club card in a single draw is $p = \frac{13}{52} = \frac{1}{4}$.The probability o

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$27$

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(C) Let $n = 4$ be the number of trials.The probability of drawing a club card in a single draw is $p = \frac{13}{52} = \frac{1}{4}$.The probability of not drawing a club card is $q = 1 - p = 1 - \frac{1}{4} = \frac{3}{4}$.Using the binomial distribution formula $P(X = k) = \binom{n}{k} p^k q^{n-k}$, where $k = 2$:$P(X = 2) = \binom{4}{2} \left(\frac{1}{4}ight)^2 \left(\frac{3}{4}ight)^{4-2}$$P(X = 2) = 6 	imes \left(\frac{1}{16}ight) 	imes \left(\frac{9}{16}ight)$$P(X = 2) = \frac{54}{256} = \frac{27}{128}$.

Four cards are drawn successively with replacement from a well-shuffled deck of $52$ cards. The probability that exactly two cards are club cards is: (in $/128$)

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