Four convergent lenses have focal lengths 100 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The magnification $m$ of an astronomical telescope is given by the formula $m = -\frac{f_o}{f_e}$,where $f_o$ is the focal length of the objective

Vedclass · Accepted Answer

$100 \, cm, 0.3 \, cm$

Vedclass · Answer

(A) The magnification $m$ of an astronomical telescope is given by the formula $m = -\frac{f_o}{f_e}$,where $f_o$ is the focal length of the objective lens and $f_e$ is the focal length of the eyepiece.To maximize the magnification $m$,we need to maximize the ratio $\frac{f_o}{f_e}$.This is achieved by choosing the largest available focal length for the objective lens $(f_o = 100 \, cm)$ and the smallest available focal length for the eyepiece $(f_e = 0.3 \, cm)$.Therefore,the lenses with focal lengths $100 \, cm$ and $0.3 \, cm$ should be chosen.

Four convergent lenses have focal lengths $100 \, cm, 10 \, cm, 4 \, cm$ and $0.3 \, cm$. For a telescope with maximum possible magnification,we choose the lenses of focal length

Similar Questions

The focal lengths of the objective and eye-piece of a telescope are $100 \ cm$ and $2 \ cm$ respectively. The moon subtends an angle of $0.5^o$ at the eye. If it is viewed through the telescope, the angle subtended by the moon's image will be......$^o$.

$A$ small telescope has an objective lens of focal length $140\, cm$ and an eyepiece of focal length $5.0\, cm$. What is the magnifying power of the telescope for viewing distant objects when the telescope is in normal adjustment?

For an astronomical telescope,the focal length of the objective lens is $f_{0}$ and the eyepiece lens is $f_{e}$. Then the tube length of the telescope is . . . . . . .

In an astronomical telescope,the focal length of the objective lens is $100 \, cm$ and of the eyepiece is $2 \, cm$. The magnifying power of the telescope for the normal eye is:

In an astronomical telescope in normal adjustment,a straight black line of length $L$ is drawn on the objective lens. The eyepiece forms a real image of this line. The length of this image is $l$. The magnification of the telescope is

Vedclass Test Series

Exam Paper Generator

Online Exam Module