Four identical resistors are connected in series with a battery,dissipating $20 \ W$ of power. What will be the power dissipated if the same resistors are connected in parallel to the same battery (in $W$)?

$A$ wire of resistance $12 \, \Omega/m$ is bent to form a complete circle of radius $10 \, cm$. The resistance between its two diametrically opposite points, $A$ and $B$, as shown in the figure, is:

The total power dissipated in watts in the circuit shown is ............. $W$.

The equivalent resistance of a group of resistances is $R$. If another resistance is connected in parallel to the group,its new equivalent becomes $R_1$,and if it is connected in series to the group,its new equivalent becomes $R_2$. We have:

In the figure shown,what is the current (in Ampere) drawn from the battery? You are given $R_1 = 15\,\Omega$,$R_2 = 10\,\Omega$,$R_3 = 20\,\Omega$,$R_4 = 5\,\Omega$,$R_5 = 25\,\Omega$,$R_6 = 30\,\Omega$,and $E = 15\,V$.

Two bulbs,one of $200 \,W$ and the other of $100 \,W$ are connected in series with a $100 \,V$ battery which has no internal resistance. Then,