Friedel-Crafts reaction using MeCl and anhydr | vedclass

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(D) The Friedel-Crafts reaction is an electrophilic aromatic substitution reaction. It requires an electron-rich aromatic ring to react efficiently wi

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toluene

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(D) The Friedel-Crafts reaction is an electrophilic aromatic substitution reaction. It requires an electron-rich aromatic ring to react efficiently with the electrophile $(CH_3^+)$. Nitrobenzene and acetophenone contain electron-withdrawing groups ($-NO_2$ and $-COCH_3$ respectively), which deactivate the benzene ring towards electrophilic substitution. Benzene is moderately reactive. Toluene contains a methyl group $(-CH_3)$, which is an electron-donating group due to the $+I$ effect and hyperconjugation. This increases the electron density of the benzene ring, making it the most reactive among the given options towards electrophilic substitution.

Friedel-Crafts reaction using $MeCl$ and anhydrous $AlCl_3$ will take place most efficiently with

Similar Questions

Arrange the following compounds in the increasing order of their reactivity towards electrophilic aromatic substitution:
$(I)$ Benzene
$(II)$ Toluene $(C_6H_5CH_3)$
$(III)$ Anisole $(C_6H_5OCH_3)$
$(IV)$ Benzaldehyde $(C_6H_5CHO)$

Which of the following has delocalised electrons?

Which of the following groups have an activating effect on the benzene ring?
$-OH, -COCH_3, -NO_2, -NH_2, -Cl, -Br, -NHCOCH_3, -COOH$

Identify the aromatic compound.

Which of the following reagents and conditions convert benzene to chlorobenzene?

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