From a mating of two dihybrid individuals (Aa | vedclass

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(D) In a dihybrid cross $(AaBb 	imes AaBb)$,the phenotypic ratio is $9:3:3:1$. The total number of combinations is $16$.To find the number of zygotes

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Six

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(D) In a dihybrid cross $(AaBb 	imes AaBb)$,the phenotypic ratio is $9:3:3:1$. The total number of combinations is $16$.To find the number of zygotes with exactly $2$ dominant genes,we look at the genotypes:$1$. $AAbb$ (contains $2$ dominant genes: $A, A$)$2$. $aaBB$ (contains $2$ dominant genes: $B, B$)$3$. $AaBb$ (contains $2$ dominant genes: $A, B$)$4$. $AaBb$ (contains $2$ dominant genes: $A, B$)$5$. $AaBb$ (contains $2$ dominant genes: $A, B$)$6$. $AaBb$ (contains $2$ dominant genes: $A, B$)Thus,there are $6$ combinations that contain exactly $2$ dominant genes.

From a mating of two dihybrid individuals $(AaBb \times AaBb)$,how many of the $16$ possible zygote combinations would be expected to contain only two dominant genes?

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