From a solid right circular cylinder with hei | vedclass

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(B) The volume of the remaining solid is calculated by subtracting the volume of the cone from the volume of the cylinder.Volume of cylinder = $\pi r^

Vedclass · Accepted Answer

$754.3$

Vedclass · Answer

(B) The volume of the remaining solid is calculated by subtracting the volume of the cone from the volume of the cylinder.Volume of cylinder = $\pi r^2 h = \pi 	imes 6^2 	imes 10 = 360\pi \ cm^3$.Volume of cone = $\frac{1}{3} \pi r^2 h = \frac{1}{3} 	imes \pi 	imes 6^2 	imes 10 = 120\pi \ cm^3$.Remaining volume = $360\pi - 120\pi = 240\pi \ cm^3$.Using $\pi \approx 3.14159$,the volume is $240 	imes 3.14159 \approx 753.98 \ cm^3$,which rounds to $754.3 \ cm^3$ when using $\pi \approx \frac{22}{7}$ $(240 	imes \frac{22}{7} \approx 754.28 \ cm^3)$.

From a solid right circular cylinder with height $10 \ cm$ and radius of the base $6 \ cm$,a right circular cone of the same height and base is removed. The volume (in $cm^3$) of the remaining solid is

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