According to Kirchhoff's law,the ratio of emi | vedclass

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(B) Kirchhoff's law of radiation states that for an arbitrary body emitting and absorbing thermal radiation in thermodynamic equilibrium,the ratio of

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Equal to the emissive power of a black body at the same temperature.

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(B) Kirchhoff's law of radiation states that for an arbitrary body emitting and absorbing thermal radiation in thermodynamic equilibrium,the ratio of its emissive power $(E)$ to its absorptive power $(a)$ is equal to the emissive power of a perfect black body $(E_b)$ at the same temperature.Mathematically,this is expressed as: $\frac{E}{a} = E_b$.Therefore,the ratio is equal to the emissive power of a black body at the same temperature.

According to Kirchhoff's law,the ratio of emissive power to absorptive power for all bodies is:

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