If 150 ,J of energy is incident on an area of | vedclass

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(B) When thermal radiation $(Q)$ falls on a body,it is partly reflected $(Q_{r})$,partly absorbed $(Q_{a})$,and partly transmitted $(Q_{t})$.The total

Vedclass · Accepted Answer

$45$

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(B) When thermal radiation $(Q)$ falls on a body,it is partly reflected $(Q_{r})$,partly absorbed $(Q_{a})$,and partly transmitted $(Q_{t})$.The total energy incident is given by $Q = Q_{a} + Q_{r} + Q_{t}$.Dividing by $Q$,we get the relation: $a + r + t = 1$,where $a$ is the coefficient of absorption,$r$ is the coefficient of reflection,and $t$ is the coefficient of transmission.Given: $Q = 150 \,J$,$Q_{r} = 15 \,J$,and $a = 0.6$.The coefficient of reflection $r = \frac{Q_{r}}{Q} = \frac{15}{150} = 0.1$.Using the relation $a + r + t = 1$:$0.6 + 0.1 + t = 1$$0.7 + t = 1$$t = 0.3$.The energy transmitted $Q_{t} = t 	imes Q = 0.3 	imes 150 \,J = 45 \,J$.

If $150 \,J$ of energy is incident on an area of $2 \,m^{2}$. If $Q_{r}=15 \,J$ and the coefficient of absorption is $0.6$,then the amount of energy transmitted is: (in $\,J$)

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