From the following masses,the one which is ex | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The precision of a measurement is determined by the number of decimal places.$1 \ g = 1000 \ mg$,which means $0.001 \ g = 1 \ mg$.To express a mas

Vedclass · Accepted Answer

$16.428$

Vedclass · Answer

(C) The precision of a measurement is determined by the number of decimal places.$1 \ g = 1000 \ mg$,which means $0.001 \ g = 1 \ mg$.To express a mass nearest to the milligram,the value must be measured up to three decimal places (i.e.,the thousandths place in grams).Comparing the options:$16 \ g$ has $0$ decimal places.$16.4 \ g$ has $1$ decimal place.$16.428 \ g$ has $3$ decimal places,which corresponds to the milligram precision $(16428 \ mg)$.$16.4284 \ g$ has $4$ decimal places,which is more precise than the milligram level.Therefore,$16.428 \ g$ is the value expressed nearest to the milligram.

From the following masses,the one which is expressed nearest to the milligram is (in $g$)

Similar Questions

$A$ jug contains $2 \ L$ of milk. Calculate the volume of the milk in $m^{3}$.

What is the density of water in $kg \ dm^{-3}$ if its density in $g \ cm^{-3}$ is $0.863$?

In the final answer of the expression $\frac{(29.2 - 20.2)(1.79 \times 10^5)}{1.37}$,the number of significant figures is

If the speed of light is $3.0 \times 10^8 \ ms^{-1}$,calculate the distance covered by light in $2.00 \ ns$. (in $m$)

Dimensions of pressure are same as that of

Vedclass Test Series

Exam Paper Generator

Online Exam Module