From the following polynomials,find out which | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine if $(x-1)$ is a factor of the polynomial $p(x) = 2x^3 + 5x^2 - x - 6$,we use the Factor Theorem.According to the Factor Theorem,$(x-a

Vedclass · Accepted Answer

Yes,it is a factor.

Vedclass · Answer

(A) To determine if $(x-1)$ is a factor of the polynomial $p(x) = 2x^3 + 5x^2 - x - 6$,we use the Factor Theorem.According to the Factor Theorem,$(x-a)$ is a factor of $p(x)$ if $p(a) = 0$.Here,$a = 1$.Substitute $x = 1$ into the polynomial:$p(1) = 2(1)^3 + 5(1)^2 - (1) - 6$$p(1) = 2(1) + 5(1) - 1 - 6$$p(1) = 2 + 5 - 1 - 6$$p(1) = 7 - 7 = 0$.Since $p(1) = 0$,$(x-1)$ is a factor of the given polynomial.

From the following polynomials,find out which of them has $(x-1)$ as a factor:
$p(x) = 2x^3 + 5x^2 - x - 6$

Similar Questions

Write the following cube in expanded form:
$(2a - 5b)^3$

Classify the following as a constant,linear,quadratic,or cubic polynomial:
$y^{3}-y$

Using the remainder theorem,find the remainder when the polynomial $p(x) = x^{3} + x^{2} - 26x + 24$ is divided by the divisor $x - 6$.

Classify the following as a constant,linear,quadratic,or cubic polynomial:
$4-5 y^{2}$

Factorise the following quadratic polynomial by splitting the middle term:
$6x^2 + 19x + 10$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

From the following polynomials,find out which of them has $(x-1)$ as a factor:$p(x) = 2x^3 + 5x^2 - x - 6$