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(A) To determine if $(x+1)$ is a factor of the polynomial $p(x) = x^{3} + 10x^{2} + 23x + 14$,we use the Factor Theorem.According to the Factor Theore

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(A) To determine if $(x+1)$ is a factor of the polynomial $p(x) = x^{3} + 10x^{2} + 23x + 14$,we use the Factor Theorem.According to the Factor Theorem,$(x+1)$ is a factor of $p(x)$ if $p(-1) = 0$.Substitute $x = -1$ into the polynomial:$p(-1) = (-1)^{3} + 10(-1)^{2} + 23(-1) + 14$$p(-1) = -1 + 10(1) - 23 + 14$$p(-1) = -1 + 10 - 23 + 14$$p(-1) = 9 - 23 + 14$$p(-1) = -14 + 14 = 0$Since $p(-1) = 0$,$(x+1)$ is indeed a factor of the given polynomial.

From the following polynomials,find out which of them has $(x+1)$ as a factor:
$x^{3} + 10x^{2} + 23x + 14$

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From the following polynomials,find out which of them has $(x+1)$ as a factor:$x^{3} + 10x^{2} + 23x + 14$